int Fun1(int num)
{
if(num 0)
return num;
}
else if(num 10)
return num - 10;
else
return num + 10;
if(num 10)
return num -10;
return num +10;
switch(num0)
case 0:
switch(num10)
case 1:
#include "stdio.h"
#includemath.h
void main()
double x,y,f,h;
printf("请输入x:\n");
scanf("%lf",x);
printf("请输入y:\n");
scanf("%lf",y);
if((x=0)(y0))
else if((x=0)(y=0))
printf("x=%lf,y=%lf,f=%lf\n",x,y,f);
printf("%lf",h);
#include stdio.h
#include math.h
int main(void)
int repeat, ri;
double x, y;
scanf("%d", repeat);
for(ri = 1; ri = repeat; ri++){
double x, y, f;
scanf("%lf%lf", x, y);
if(x=0 y0)
else if(x=0 y=0)
printf("x=%lf, y=%lf, f(x, y)=%lf\n", x, y, f);
return 0;
if(x=0)
if(y0)
int score = 0;
printf("Please input a score between 0-100:\n");
scanf("%d", score);
if(score0 || score100)
printf("Wrong input of score!\n");
printf("A\n");
printf("B\n");
printf("C\n");
printf("D\n");
printf("E\n");
①.、编写如下:
//100分制
int score,t;
printf("输入成绩:");
scanf("%d",score);
switch(t)
case 10:printf("优秀\n");break;
{ f=x+1; if ( f0 ) f=-f; }
x,f);
计算下列分段函数
扩展资料:
求分段函数的函数值的方法:先确定要求值的自变量属于哪一段区间,然后按该段的表达式去求值,直到求出值为止.
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