vb.net开平方

求VB平方镜反数怎么编程

以下是平方镜在vb.net中的程序,需要一个 listbox和command

Public Class Form1

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click

Dim xx As Long, j As String, i As String

xx = InputBox("请输入最大范围数", 100000)

For m = 10 To xx

i = m

j = StrReverse(i)

If i = j Then GoTo 10

End If

①.0:

Next

End Sub

End Class

VB.NET 简单多线程

多线程一般是不推荐用的,因为线程之间如果有共享资源的话会引起竞争,需要加锁处理；而且线程间没有时序关系,所以你在调试中可能会出现异步处理结束顺序与开始处理顺序不一致的情况（我在调试中已经发现该问题）.

针对你提出的这个问题,采用了多线程处理,利用的是BackgroundWorker也就是异步处理控件进行了处理.

代码已经经过调试通过.欢迎交流,如有问题,留下QQ或其他联系方式.

代码如下,并附程序截图.

'---------------------------------------------------

Imports?System.ComponentModel?'导入异步控件命名空间

Public?Class?Form1

Private?howmany?As?Integer?=?10

Private?AnalysisNumber(0?To?howmany?-?1)?As?BackgroundWorker

Private?Sub?Button1_Click(ByVal?sender?As?System.Object,?ByVal?e?As?System.EventArgs)?Handles?Button1.Click

ListBox1.Items.Clear()

creatNewBackgroundWorker()

addHandle()

startWork()

End?Sub

Private?Sub?creatNewBackgroundWorker()

For?i?As?Integer?=?0?To?AnalysisNumber.Length?-?1

AnalysisNumber(i)?=?New?BackgroundWorker

Private?Sub?addHandle()

AddHandler?AnalysisNumber(i).DoWork,?AddressOf?AnalysisNumber_DoWork

AddHandler?AnalysisNumber(i).RunWorkerCompleted,?AddressOf?AnalysisNumber_RunWorkerCompleted

Private?Sub?startWork()

For?j?As?Integer?=?1?To?10

temp(j?-?1)?=?10?*?i?◆?j

AnalysisNumber(i).RunWorkerAsync(temp)

Private?Sub?AnalysisNumber_DoWork(ByVal?sender?As?Object,?ByVal?e?As?System.ComponentModel.DoWorkEventArgs)

Dim?data?As?Integer()

data?=?CType(e.Argument,?Integer())

Dim?temp?As?Integer

For?i?As?Integer?=?0?To?data.Length?-?1

temp?=?data(i)

data(i)?=?temp?*?temp

e.Result?=?data

Private?Sub?AnalysisNumber_RunWorkerCompleted(ByVal?sender?As?Object,?ByVal?e?As?System.ComponentModel.RunWorkerCompletedEventArgs)

data?=?CType(e.Result,?Integer())

ListBox1.Items.Add(data(i))

End?Class

VB.NET为用户提供了Math.Sqrt函数用于计算平方根值,但被开方值若为负数则无法得出正确的结果（如,-4的平

问题不是很简单吗?

判断输入的数,大于等于零,则直接开方;小于零则取绝对值开方再加上字符"i",代码我就不写了.

vb.net求双平方数字的的方法

Public?Function?panduan(ByVal?n?As?Integer)?As?Boolean

Dim?res?As?Boolean?=?False

a?=?n?\?1000

b?=?(n?\?100)?Mod?10

c?=?(n?\?10)?Mod?10

d?=?n?Mod?10

temp1?=?Sqrt(n)

res?=?True

End?If

Return?res

End?Function

Dim?str?As?String?=?"",?temp?As?Integer?=?0,?sum?As?Integer?=?0,?x?As?Integer

If?panduan(i)?Then

temp?=?i

Exit?For

VB.net的开方运算

VB的运算顺序是：先乘除、后加减,有括号的先算括号内,有负号的先算负号.

请你比较一下这个运算中x和y的值：

Dim x As Single

Dim y As Single

x = n ◆ 1

x = x / n

x = x - 1

x = Math.Sqrt(x)

y = Math.Sqrt((n ◆ 1) / n - 1)

这样就会发现,你的代码中括号的位置错了.

正确的应该是： Math.Sqrt((n ◆ 1) / n - 1)

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