java歌词代码

java解析lrc文件代码

lrc可以通过如下util工具类进行转换,如果想知道结果是否读取的有问题,可以直接用记事本打开lrc文件的,之后和输出结果比对一下就行.

package com.routon.utils;

import java.io.BufferedReader;

import java.io.FileInputStream;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.ArrayList;

import java.util.List;

import java.util.regex.Matcher;

import java.util.regex.Pattern;

import android.util.Log;

/**

* parse lrc file tool

* eg：

* utilLrc lrc = new utilLrc("/sdcard/test.lrc");

* get song name : String title = lrc.getTitle();

* get performer name : String artist = lrc.getArtist();

* get album name: String album = lrc.getAlbum();

* get lrcmaker name: String lrcMaker = lrc.getLrcMaker();

* get song list: ListStatement list = lrc.getLrcList();

*

* @author xuweilin

*/

public class utilLrc {

private static String TAG = "utilLrc";

public class Statement {

private double time = 0.0;//time, 0.01s

private String lyric = "";//song word

/*

* get time

public double getTime() {

return time;

}

* set time

public void setTime(double time) {

this.time = time;

* set time.format:mm:ss.ms

public void setTime(String time) {

String str[] = time.split(":|\\.");

* get lrc word

public String getLyric() {

return lyric;

* set lrc word

public void setLyric(String lyric) {

this.lyric = lyric;

private BufferedReader bufferReader = null;

private String title = "";

private String artist = "";

private String album = "";

private String lrcMaker = "";

private ListStatement statements = new ArrayListStatement();

* fileName

public utilLrc(String fileName) throws IOException{

FileInputStream file = new FileInputStream(fileName);

readData();

* read the file

private void readData() throws IOException{

statements.clear();

String strLine;

while(null != (strLine = bufferReader.readLine()))

{

if("".equals(strLine.trim()))

continue;

if(null == title || "".equals(title.trim()))

Pattern pattern = Pattern.compile("\\[ti:(.+?)\\]");

Matcher matcher = pattern.matcher(strLine);

if(matcher.find())

title=matcher.group(1);

if(null == artist || "".equals(artist.trim()))

Pattern pattern = Pattern.compile("\\[ar:(.+?)\\]");

artist=matcher.group(1);

if(null == album || "".equals(album.trim()))

Pattern pattern = Pattern.compile("\\[al:(.+?)\\]");

album=matcher.group(1);

if(null == lrcMaker || "".equals(lrcMaker.trim()))

Pattern pattern = Pattern.compile("\\[by:(.+?)\\]");

lrcMaker=matcher.group(1);

int timeNum=0;

String str[] = strLine.split("\\]");

for(int i=0; istr.length; ++i)

if(isTime(str[i])){

++timeNum;

for(int i=0; itimeNum;++i)

Statement sm = new Statement();

sm.setTime(str[i]);

if(timeNumstr.length)

sm.setLyric(str[str.length-1]);

statements.add(sm);

sortLyric();

* judge the string is or not date format.

private boolean isTime(String string)

String str[] = string.split(":|\\.");

return false;

try{

for(int i=0;istr.length;++i)

Integer.parseInt(str[i]);

catch(NumberFormatException e)

Log.e(TAG, "isTime exception："+e.getMessage());

return true;

* sort the word by time.

private void sortLyric()

for(int i=0;istatements.size()-1;++i)

int index=i;

double delta=Double.MAX_VALUE;

boolean moveFlag = false;

for(int j=i+1;jstatements.size();++j)

double sub;

if(0=(sub=statements.get(i).getTime()-statements.get(j).getTime()))

moveFlag=true;

if(subdelta)

delta=sub;

index=j+1;

if(moveFlag)

statements.add(index, statements.get(i));

statements.remove(i);

--i;

* get title

* @return

public String getTitle(){

return title;

* get artist

public String getArtist(){

return artist;

* get album

public String getAlbum(){

return album;

* get lrc maker

public String getLrcMaker(){

return lrcMaker;

* get song list

public ListStatement getLrcList(){

return statements;

求教,急用！JAVA按歌词文件的时间标签从小到大排列内容,然后最好能给我做个方法,让我直接调用,排

土嘎嘎的粉丝们大家好,这是你要的方法,直接输入路径调用就可以了,输出结果是sorted-加原文件名

*?根据路径和编码?重新排列歌词中的文件,转换后的文件是"sorted-原文件"

public?static?void?sortLyric(String?source)?{

try?{

ListString?lines?=?new?ArrayListString();

String?line;

while?((line?=?br.readLine())?!=?null)?{

lines.add(line);

br.close();

Collections.sort(lines);

for?(String?everyLine?:?lines)?{

bw.write(everyLine);

bw.newLine();

bw.flush();

bw.close();

}?catch?(Exception?e)?{

e.printStackTrace();

在java中怎么从键盘输入一段歌词以空格用split()分割

public static void main(String[] args) {

// TODO 自动生成的方法存根

Scanner sc = new Scanner(System.in);

System.out.println("请输入歌词:");

String s = sc.nextLine();

String[] x = s.split(" ");

for(int i = 0;ix.length;i++){

System.out.println(x[i]);

JAVA截取字符串(截取歌词)

把歌词存在一个叫 geci.txt 的文本中 放在D盘根目录

import java.io.FileNotFoundException;

import java.io.FileReader;

public class SaveSong {

* @param args

// TODO Auto-generated method stub

BufferedReader br = null;

String lineContent = "";

String[] s = new String[100];

int i = 0;

try {

br = new BufferedReader(new FileReader("D:\\geci.txt"));

} catch (FileNotFoundException e1) {

// TODO Auto-generated catch block

e1.printStackTrace();

while ((lineContent = br.readLine()) != null) {

System.out.println(lineContent);

s[i]= lineContent;

i++;

} catch (IOException e) {

用java写程序 显示一首歌的一段歌词 并标注和声部分

很简单啊,创建一个类,再建一个方法,在里面创建一个String类型变量,里面放入你想放入的歌词,标注也可以加在里面.

java 正则表达式 匹配[00:00.00]或者[00:00]这两种歌词时间格式的正则表达式

下面的代码就是你想要的:

Pattern p = Pattern.compile(regx1);

Matcher m = p.matcher(str);

if(!m.matches()){

m = p.matcher(str);

System.out.println("输入格式不符合要求!");

}else{

System.out.println("输入格式正确!　匹配格式为:"+"[00:00]");

System.out.println("输入格式正确!　匹配格式为:"+"[00:00.00]");

以上就是土嘎嘎小编为大家整理的java歌词代码相关主题介绍,如果您觉得小编更新的文章只要能对粉丝们有用,就是我们最大的鼓励和动力,不要忘记讲本站分享给您身边的朋友哦！！