java问卷调查代码

如何用java设计一个简单的问卷调查?

推荐使用专业的问卷调查平台,通太问卷调查就可以,使用JAVA编写的.

JAVA设计一个Applet,完成一份调查问卷,至少包括五个题目,

import java.applet.Applet;

import java.awt.Color;

import java.awt.Font;

import java.awt.Graphics;

public class DrawString extends Applet {

public void paint(Graphics g)

{

g.setColor(Color.green);

g.setColor(Color.red);

}

使用java编写代码如下要求

NewPhone类

package?com.baidu.question;

public?class?NewPhone?extends?Phone?{

private?boolean?mute?=?true;

public?void?call()?{

if(mute){

super.call();

}else{

System.out.println("语音已关闭");

//这里是直接设置

public?void?setMute(boolean?mute){

this.mute=mute;

//担心你的题目是要求两种方法,写的第二种,下面两个方法负责开关

public?void?openMute(){

this.mute=true;

/*

*?也可以这样写

*?setMute(true);

*?下边的方法一样

*?*/

public?void?closeMute(){

this.mute?=?false;

Phone类

public?class?Phone?{

public?void?call(){

System.out.println("打电话");

测试类

public?class?PhoneTest?{

public?static?void?main(String[]?args)?{

Phone?phone?=?new?Phone();

phone.call();

NewPhone?newPhone?=?new?NewPhone();

newPhone.call();

newPhone.setMute(false);

newPhone.openMute();

newPhone.closeMute();

测试结果

打电话

语音已关闭

java中想动态设置radio的name属性

你的意思是不是在下一页得到name的值．

如果是的话

可以

session.setAttribute("radioName",id)

然后在下一页

String radioName=(String)session.getAttribute("radioName");

不过感觉你的循环有问题,一题只有一个选项．

.给出存储班级三十名学生基本信息的Java代码,基本信息的具体赋值由考生自拟?

下面是一个存储班级三十名学生基本信息的 Java 代码示例：

import java.util.ArrayList;

public class Student {

private String name;

private int age;

private String gender;

public Student(String name, int age, String gender) {

this.name = name;

this.age = age;

this.gender = gender;

public String getName() {

return name;

public int getAge() {

return age;

public String getGender() {

return gender;

public class Classroom {

private ArrayListStudent students;

public Classroom() {

this.students = new ArrayListStudent();

public void addStudent(Student student) {

students.add(student);

public ArrayListStudent getStudents() {

return students;

public class Main {

public static void main(String[] args) {

Classroom classroom = new Classroom();

// ...

// 获取所有学生的信息

ArrayListStudent students = classroom.getStudents();

for (Student student : students) {

System.out.println("Name: " + student.getName());

System.out.println("Age: " + student.getAge());

System.out.println("Gender: " + student.getGender());

该代码定义了两个类：Student 类表示一个学生,包含了学生的姓名、年龄和性别等信息；Classroom 类表示一个班级,包含了一个学生的列表,并提供了添加学生和获取学生列表的方法.

请问以下问题用java代码来求解应该是怎么写

import java.util.Scanner;

/**

* @Author: Cool_Wu

*/

public class Transport {

private static final int BOX_A = 1;

private static int count_A;

private static int count_B;

? ?System.out.println("请输入宝物数量：");

? ?int count = new Scanner(System.in).nextInt();

? ? ? ?System.out.println("宝物数量输入有误！");

? ? ? ?return;

? ?}

? ?for (count_B = 0; count_B = count / BOX_B; count_B++){

? ? ? ?count_A = count - count_B * BOX_B;

? ? ? ?System.out.println("盒子A装运宝物数量：" + BOX_A + "x" + count_A + "=" + BOX_A * count_A);

? ? ? ?System.out.println("盒子B装运宝物数量：" + BOX_B + "x" + count_B + "=" + BOX_B * count_B);

? ? ? ?System.out.println("宝物装运总数：" + BOX_A * count_A + "+" + BOX_B * count_B + "=" + (BOX_A * count_A + BOX_B * count_B));

? ? ? ?System.out.println("-------------------------");

? ?System.out.println("装运方案数为：" + count_B);

运行结果

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